Problem
Given two integers, an hour and a minute, write a function to calculate the angle between the two hands on a clock representing that time.
Example 1:
Input: 3, 0
Output: 90
Example 2:
Input: 3, 20
Output: 20
Example 3:
Input: 12, 0
Output: 0
Example 4:
Input: 2, 45
Output: 172.5
Example 5:
Input: 9, 0
Output: 90
Approach
Find out the degree of angle per hour (360 / 12) and minute (360 / 60). Calculate the degree of angle for minute hand (minute * angle per minute). And then calcualte the degree of angle for hour hand (hour * angle per hour) plus the degree of angle made by minute hand (minute / 60 * angle per hour). Calculate the difference in degree of angle between hour and minute hands. Finally, return the lowest degree of angles. For example, return 90 degree of angle for 9:00 instead of 270.
Solution
/**
* Calculate the clock angle
* @param {Number} hour
* @param {Number} minute
* @return {Number}
* @time comlexity: O(1)
* @space complexity: O(1)
*/
const clockAngle = (hour, minute) => {
const ANGLE_PER_HOUR = 360 / 12,
ANGLE_PER_MINUTE = 360 / 60,
minuteHand = minute * ANGLE_PER_MINUTE,
hourHand = hour * ANGLE_PER_HOUR + minute / 60 * ANGLE_PER_HOUR;
const angle = Math.abs(hourHand - minuteHand);
return Math.min(360 - angle, angle);
};
Test Case
import { assert } from 'chai';
describe('Clock Angle', () => {
it('3:00 should be 90 degree', () => {
assert.strictEqual(clockAngle(3, 0), 90);
});
it('3:20 should be 20 degree', () => {
assert.strictEqual(clockAngle(3, 20), 20);
});
it('12:00 should be 0 degree', () => {
assert.strictEqual(clockAngle(12, 0), 0);
});
it('2:45 should be 172.5 degree', () => {
assert.strictEqual(clockAngle(2, 45), 172.5);
});
it('9:00 should be 90 degree', () => {
assert.strictEqual(clockAngle(9, 0), 90);
});
});
Clock Angle
✓ 3:00 should be 90 degree
✓ 3:20 should be 20 degree
✓ 12:00 should be 0 degree
✓ 2:45 should be 172.5 degree
✓ 9:00 should be 90 degree
5 passing (156ms)
